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Free energy and equilibrium

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Problem

Two structural formulas of organic compounds are separated by two stacked arrows with half heads pointing in opposite directions. The first structure is labeled cis-2-butene and consists of a chain of H 3 C group bonded with a single bond to C atom bonded with a double bond to C atom bonded with a single bond to C H 3 group. Both C atoms of the chain are bonded with a different H atom below. Both C H 3 groups of the molecule are above, on the same side. The second structural formula is labeled trans-2-butene and consists of a chain of H 3 C group bonded with a single bond to C atom bonded with a double bond to C atom bonded with a single bond to C H 3 group. Both C atoms of the chain are bonded with a different H atom, one above and one below on opposite sides. Both C H 3 groups of the molecule are on opposite sides, one above and one below.
The gas-phase isomerization of cis-2-butene to produce trans-2-butene is represented by the equation above. The value of the standard free energy change, ΔG°rxn, for the reaction is 3.05kJ/molrxn at 298 K.
Calculate the value of the equilibrium constant, Keq, for the reaction at 298 K.
Write your answer using
  • Your answer should be
  • an integer, like 6
  • a simplified proper fraction, like 3/5
  • a simplified improper fraction, like 7/4
  • a mixed number, like 1 3/4
  • an exact decimal, like 0.75
  • a multiple of pi, like 12 pi or 2/3 pi