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Finding area with fractional sides 1

Learn how to calculate the area of rectangles with fractional side lengths. Watch examples of this concept in action and practice applying it to different problems. The video emphasizes understanding the process, not just getting the answer.

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  • blobby green style avatar for user IsabellaB
    I STILL DONT GET IT they lose me at when they did the squares
    (0 votes)
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    • blobby green style avatar for user Cordelia Liang
      Sal showed 2 ways to figure out the area or the square

      1): multiplying the width and height

      2): is to take the numerator(the top number) of each fraction, and use that to make a grid.
      Example: 5/9 is the height so top to bottom Sal separated the area into 5 sections
      after doing that with height and width it made a grid each square being 1/9 by 1/8

      He figured out the area by multiplying 1/9 by 1/8 (Which is 1/72)

      then sal figured out the number of squares by multiplying the number top to bottom then left to right (height by width) that being 7x5(35)

      and at the very end multiplied the number of squares (35)by the area or each squares(1/72) that is 35/72


      (The thing about meters squared is just a poor example you don't have to understand it)
      (13 votes)
  • starky tree style avatar for user rl30629
    When you are multiplying the height and width are you finding the area or the perimeter?
    (8 votes)
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  • duskpin sapling style avatar for user Sergio Barranco
    I don't understand the relationship of 8 and 9.
    7x5 seems logic however where did you get 8/9 from?
    (7 votes)
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  • orange juice squid orange style avatar for user kbramlett
    clarify why you split the rectangle into 35 equal parts. It seems random. Please point out that you are using the numerators of both fractions to divide it into equal parts and why.
    (5 votes)
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  • blobby green style avatar for user thesimplevida
    how ado you times a fraction by a normal number
    (3 votes)
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  • sneak peak green style avatar for user anthony S ひ
    clarify why you split the rectangle into 35 equal parts. It seems random. Please point out that you are using the numerators of both fractions to divide it into equal parts and why?...
    (2 votes)
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  • duskpin tree style avatar for user Charlotte    Mitchell
    Your method does not work with the problem I have
    (1 vote)
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  • male robot donald style avatar for user Collin 🤫🧏🤫🧏🤫🧏
    So we've got a rectangle here, it's five-ninths of a meter tall, and seven-eighths of a meter wide. What is its area? And I encourage you to pause the video to think about that. Well one way to think about it, is you can say our area, our area is just going to be the width times the height. We're just going to multiply these two dimensions. And so the width is seven-eighths of a meter. So it's going to be seven-eighths of a meter times the height, times the height which is five-ninths of a meter. Times five-ninths of a meter. And what's that going to get us? Well, that's just going to be equal to the meters times the meters give us square meters, so meters squared. We could write it like that. And then we're going have, and then we're going to have seven times, this in a new color, we're going to have seven times five in the numerator to get us 35, and then in the denominator, in the denominator we are going to have eight times nine to give us 72. And we'd be done. This is the area of this rectangle here. It's 35-72nds of a square meter. What I want to do now is think a little bit deeper about why that actually makes sense. Or just really another way of thinking about it. And to do that, what I'm going to do is I'm going to split this region into equal rectangles. So let's split it into equal rectangles. And we see that we have seven, if we go in the horizontal direction we have one, two, three, four, five, six, seven or you could say in each row we have seven of these rectangles. In each column you have one, two, three, four, five of these rectangles. So you can see we have five times one, two, three, four, five, six, seven. So we have five times seven of these rectangles. So, we have--so 35, we have 35 rectangles. I'll just write this, 35 rectangles. And what's the area of each of those rectangles? Well, if this is seven-eighths meters wide, and this is divided into seven equal sections in the horizontal direction, that means that each of these is exactly one-eighth of a meter wide. And by that same logic, each of these, if this whole thing is five-ninths, and the height of each of these is one-fifth because we have five rectangles per column, then the height of each of these is going to be one-ninth of a meter. So what's the area of just this character right over here? Well, it's going to be one-ninth of a meter times one-eighth of a meter. So this area, this area right over there is just going to be one-ninth of a meter times one-eighth of a meter which is equal to one times one is one, nine times eight is 72, and meters times meters is square meters. So the area of each of these 35 is one-72nd of a square meter. So, if I say 35, so the area of all of them combined is going to be 35 times the area of each of them. 35 times one-72nd of a square meter. And what's that going to be? Well, that's going to be exactly what we got up here. 35 times one-72nd of a square meter is going to be 35, 35-72nds of a square meter. And this 35 is the same one that we had in yellow. That's this one right over there. So once again, you can just multiply five-ninths times seven-eighths to get what we have got here. But hopefully when we thought about the area of each of these rectangles, it might make a little bit more intuitive sense where this number came from.
    (1 vote)
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  • hopper cool style avatar for user Austin_Wang69
    At why does it have to be 35 rectangles? Its very random in my opinion.
    (2 votes)
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    • sneak peak green style avatar for user Julie C.
      Hi Austin!

      It has to be 35 squares because that's the total amount of squares in the rectangle's area if you count each one on the screen. Each square has the same size/area of measurement and they distribute evenly (by "filling") the rectangle with no gaps or variations of size within the rectangle. Keeping each square the same size allows us to create a fraction that is from consistently measured data. If each square is consistently the same size then we know the fraction we create representing the total amount of squares (the 35 of 35/72) will be consistent and true as well.

      You could also think of it as 7 columns of squares of 5 rows of squares = 35 total squares, or 5 rows of squares by 7 seven columns of squares = 35 total squares.

      If anyone has another perspective with which to answer this question with, please feel free to add it.
      (0 votes)
  • duskpin sapling style avatar for user SCOTT, CATHY N
    You are not using square units. A unit that is 1/8 by 1/9 is not a square. Can you explain
    (1 vote)
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Video transcript

- [Voiceover] So we've got a rectangle here, it's five-ninths of a meter tall, and seven-eighths of a meter wide. What is its area? And I encourage you to pause the video to think about that. Well one way to think about it, is you can say our area, our area is just going to be the width times the height. We're just going to multiply these two dimensions. And so the width is seven-eighths of a meter. So it's going to be seven-eighths of a meter times the height, times the height which is five-ninths of a meter. Times five-ninths of a meter. And what's that going to get us? Well, that's just going to be equal to the meters times the meters give us square meters, so meters squared. We could write it like that. And then we're going have, and then we're going to have seven times, this in a new color, we're going to have seven times five in the numerator to get us 35, and then in the denominator, in the denominator we are going to have eight times nine to give us 72. And we'd be done. This is the area of this rectangle here. It's 35-72nds of a square meter. What I want to do now is think a little bit deeper about why that actually makes sense. Or just really another way of thinking about it. And to do that, what I'm going to do is I'm going to split this region into equal rectangles. So let's split it into equal rectangles. And we see that we have seven, if we go in the horizontal direction we have one, two, three, four, five, six, seven or you could say in each row we have seven of these rectangles. In each column you have one, two, three, four, five of these rectangles. So you can see we have five times one, two, three, four, five, six, seven. So we have five times seven of these rectangles. So, we have--so 35, we have 35 rectangles. I'll just write this, 35 rectangles. And what's the area of each of those rectangles? Well, if this is seven-eighths meters wide, and this is divided into seven equal sections in the horizontal direction, that means that each of these is exactly one-eighth of a meter wide. And by that same logic, each of these, if this whole thing is five-ninths, and the height of each of these is one-fifth because we have five rectangles per column, then the height of each of these is going to be one-ninth of a meter. So what's the area of just this character right over here? Well, it's going to be one-ninth of a meter times one-eighth of a meter. So this area, this area right over there is just going to be one-ninth of a meter times one-eighth of a meter which is equal to one times one is one, nine times eight is 72, and meters times meters is square meters. So the area of each of these 35 is one-72nd of a square meter. So, if I say 35, so the area of all of them combined is going to be 35 times the area of each of them. 35 times one-72nd of a square meter. And what's that going to be? Well, that's going to be exactly what we got up here. 35 times one-72nd of a square meter is going to be 35, 35-72nds of a square meter. And this 35 is the same one that we had in yellow. That's this one right over there. So once again, you can just multiply five-ninths times seven-eighths to get what we have got here. But hopefully when we thought about the area of each of these rectangles, it might make a little bit more intuitive sense where this number came from.